## Precalculus (6th Edition) Blitzer

$(-4,\frac{81}{256})$, $(-2,\frac{9}{16})$, $(-1,\frac{3}{4})$, $(1,\frac{4}{3})$, $(2,\frac{16}{9})$, $(4,\frac{256}{81})$ Graph is attached
$g(x) = (\frac{4}{3})^{x}$ Lets put x=−4,−2,−1,1,2,4 $g(-4) = (\frac{4}{3})^{-4} = \frac{81}{256}$ $g(-2) = (\frac{4}{3})^{-2} = \frac{9}{16}$ $g(-1) = (\frac{4}{3})^{-1} = \frac{3}{4}$ $g(1) = (\frac{4}{3})^{1} = \frac{4}{3}$ $g(2) = (\frac{4}{3})^{2} = \frac{16}{9}$ $g(4) = (\frac{4}{3})^{4} = \frac{256}{81}$ Plot the set of points