Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 3 - Review Exercises - Page 515: 94

Answer

$ y=6.5 e^{-0.844x} $

Work Step by Step

Recall the log rules: (a) $\log_b{\dfrac{p}{q}}=\log_b{p} - \log_b{q}$ (Quotient Rule). (b) $\log{a}=\log_{10}{a}$ (c) $\log_a{a^x}=x $ (d) $ e^{\ln a}=a $ We are given $ y=6.5(0.43)^x $ ....(1) We simplify equation (1) by using rule (d) with $ a=0.43$: $ y= 6.5e^{\ln 0.43 x}=6.5 e^{-0.844x} $
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