Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 3 - Review Exercises - Page 515: 93


$ y= 73 e^{0.956x} $

Work Step by Step

We are given: $ y=73 (2.6)^x $ We use the fact that $e^{\ln{a}}=a$, with $a=2.6$: $y= 73 e^{(\ln 2.6) x}$ $y=73 e^{0.956x} $
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