Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 2 - Section 2.8 - Modeling Using Variation - Exercise Set - Page 423: 15


The required equation is $x=k\frac{yz}{\sqrt{w}}$ and value of $y$ is $\frac{x\sqrt{w}}{kz}$.

Work Step by Step

As the value of $x$ varies jointly as $y$ and $z$ and inversely as $\ \sqrt{w}$ , we have $x=k\frac{yz}{\sqrt{w}}$ Where $k$ is a constant Now, solve the above equation for $y$. Divide $x=k\frac{yz}{\sqrt{w}}$ by $\frac{\sqrt{w}}{kz}$ , and we have $y=\frac{x\sqrt{w}}{kz}$
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