Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 2 - Section 2.8 - Modeling Using Variation - Exercise Set - Page 423: 18

Answer

The required equation is $x=kz\left( y-w \right)$ and the value of $y$ is $\frac{x+kzw}{kz}$.

Work Step by Step

As the value of $x$ varies directly as $z$ and $\left( y-w \right)$ , we have $x=kz\left( y-w \right)$ Where $k$ is a constant. Now, solve the above equation for $y$. $\begin{align} & x=kz\left( y-w \right) \\ & x=kzy-kzw \\ & kzy=x+kzw \\ & y=\frac{x+kzw}{kz} \end{align}$
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