#### Answer

$(-\infty, 18]$

#### Work Step by Step

Step 1. To find the domain for $h(x)=\sqrt {36-2x}$, let $36-2x\geq0$; we have $2x\leq36$ and $x\leq18$
Step 2. Thus, the domain is $(-\infty, 18]$

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Published by
Pearson

ISBN 10:
0-13446-914-3

ISBN 13:
978-0-13446-914-0

$(-\infty, 18]$

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