Answer
$(-\infty, 18]$
Work Step by Step
Step 1. To find the domain for $h(x)=\sqrt {36-2x}$, let $36-2x\geq0$; we have $2x\leq36$ and $x\leq18$
Step 2. Thus, the domain is $(-\infty, 18]$
Precalculus (6th Edition) Blitzer
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13446-914-3
ISBN 13:
978-0-13446-914-0
Chapter 2 - Section 2.7 - Polynomial and Rational Inequalities - Exercise Set - Page 415: 111
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