Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 2 - Section 2.7 - Polynomial and Rational Inequalities - Exercise Set - Page 415: 103


The required inequality is $\frac{x-3}{x+4}\ge 0$.

Work Step by Step

Consider the inequality is $\frac{x-3}{x+4}\ge 0$. Multiply both sides by ${{\left( x+4 \right)}^{2}},x\ne -4$. ${{\left( x+4 \right)}^{2}}\frac{x-3}{x+4}\ge 0\times {{\left( x+4 \right)}^{2}}$ Solve further: $\left( x+4 \right)\left( x-3 \right)\ge 0$ Which implies the solution: $(-\infty,-4)\cup [3,\infty)$
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