Answer
$(-2,-1)\cup(2,\infty)$
Work Step by Step
Step 1. Graph the function $f(x)=x^3+x^2-4x-4$ as shown in the figure.
Step 2. The zeros of the function can be identified as $x=-2,-1,2$
Step 3. We can identify the regions where $f(x)\gt0$ as $(-2,-1)\cup(2,\infty)$
