## Precalculus (6th Edition) Blitzer

In the rational function, the $y$ intercept is determined by putting the value of the $x$ variable as $0$ in the function’s equation and then calculating the value of the y-coordinate. But, there are some rational functions that are not defined at $x=0$. For such functions, $x=0$ is the vertical asymptote, and hence, they don’t have any y-intercept. Example: $y=\frac{1}{{{x}^{2}}}$ has the vertical asymptote at $x=0$. Thus, the given statement is true.