Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 2 - Section 2.6 - Rational Functions and Their Graphs - Exercise Set - Page 400: 99

Answer

a. $C(x)=100000+100x$ b. $\bar C(x)=100+\frac{100000}{x}$ c. $\bar C(500)=300$, $\bar C(1000)= 200$, $\bar C(2000)=150$, $\bar C(4000)125$ d. $\bar C=100$. See explanations.

Work Step by Step

a. Based on the given conditions, we have $C(x)=100000+100x$ b. The average cost is given by $\bar C(x)=\frac{100000+100x}{x}=100+\frac{100000}{x}$ c. (i) Using the given values, we have $\bar C(500)=100+\frac{100000}{500}=100+200=300$ dollars (the average cost to produce 500 bikes is 300 dollars). (ii) Similarly, we have $\bar C(1000)=100+\frac{100000}{1000}=100+100=200$ dollars (the average cost to produce 1000 bikes is 200 dollars). (iii) $\bar C(2000)=100+\frac{100000}{2000}=100+50=150$ dollars (the average cost to produce 2000 bikes is 150 dollars). (iv) $\bar C(4000)=100+\frac{100000}{4000}=100+25=125$ dollars (the average cost to produce 4000 bikes is 125 dollars). d. The horizontal asymptote can be found by letting $x\to\infty$, which gives $\bar C=100$. This means that when the number of bikes produced is extremely large, the average cost will be close to 100 dollars.
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