Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 2 - Section 2.6 - Rational Functions and Their Graphs - Exercise Set - Page 400: 96

Answer

The graph of the function $g\left( x \right)=\frac{1}{x+2}+3:$

Work Step by Step

Convert the function into the form: $\text{quotient}+\frac{\text{remainder}}{\text{divisor}}$. $\begin{align} & g\left( x \right)=\frac{3x+7}{x+2} \\ & g\left( x \right)=3+\frac{1}{x+2} \end{align}$ Where quotient is $3$ , remainder is $1,$ and divisor is $x+2$. The rational root is $\begin{align} & x+2=0 \\ & x=-2 \end{align}$ When x is changed to $x+a$, this implies that the graph of the function is shifted by a units to the left.The graph of the function $f\left( x \right)=\frac{1}{x+2}$ is shifted left by 2 units. The graph has a vertical asymptote along $x=-2$. The graph has a horizontal asymptote along $y=3$.
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