Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 2 - Section 2.6 - Rational Functions and Their Graphs - Exercise Set - Page 398: 4

Answer

Domain of\[f=\left\{ x|x\ne 2,x\ne -6 \right\}\]

Work Step by Step

Division by zero is undefined, so exclude from the domain each function value of x for which the denominator is zero. The denominator of $g\left( x \right)=\frac{2{{x}^{2}}}{\left( x-2 \right)\left( x+6 \right)}$ is 0 if $x=2$ and $x=-6$ Thus, x cannot be 2 and -6. Domain of $f=\left\{ x|x\ne 2,x\ne -6 \right\}$.
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