Answer
Domain of\[f=\left\{ x|x\ne 8,x\ne -8 \right\}\]
Work Step by Step
Division by zero is undefined, so exclude from the domain each function value of x for which the denominator is zero.
The denominator of $h\left( x \right)=\frac{x+8}{{{x}^{2}}-64}$ is 0 if $x=8$ and $x=-8$.
Thus, x is not equal to 8 and -8.
Domain of $f=\left\{ x|x\ne 8,x\ne -8 \right\}$.
