Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 2 - Section 2.5 - Zeros of Polynomial Functions - Exercise Set - Page 380: 91

Answer

$x=3\ in$.
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Work Step by Step

Step 1. The volume of the solid can be expressed as the difference between the large rectangular prism and the empty slot; that is $V=(x+2)(2x+1)(x+5)-3x(x+5)=(x+5)(2x^2+5x+2-3x)=2(x+5)(x^2+x+1)$ Step 2. Letting $V=208$, we have $x^3+x^2+x+5x^2+5x+5=104$ or $x^3+6x^2+6x-99=0$ Step 3. Use synthetic division to find a zero $x=3$ as shown in the figure. Then, the equation becomes $(x-3)(x^2+9x+33)=0$ Step 4. We can find that the only real solution to the above equation is $x=3\ in$.
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