Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 2 - Section 2.5 - Zeros of Polynomial Functions - Exercise Set - Page 380: 100

Answer

The average rate of change of $f\left( x \right)=\sqrt{x}$ from ${{x}_{1}}=4$ to ${{x}_{2}}=9$ is $\underline{\frac{1}{5}}$.

Work Step by Step

The average rate of change: $\begin{align} & r=\frac{f\left( 9 \right)-f\left( 4 \right)}{9-4} \\ & =\frac{\sqrt{9}-\sqrt{4}}{9-4} \\ & =\frac{3-2}{5} \\ & =\frac{1}{5} \end{align}$ Therefore, the average rate of change is $\frac{1}{5}$.
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