## Precalculus (6th Edition) Blitzer

a. $x=-3$, even multiplicity, $x=2$, even multiplicity b. $y=-(x+3)^2(x-2)^2$ c. $y=-36$
a. zeros: $x=-3$, even multiplicity, $x=2$, even multiplicity b. We can write the equation as $y=-(x+3)^2(x-2)^2$ c. The y-intercept can be found as $y=-36$ from the above equation by letting $x=0$, or by reading from the given graph.