Precalculus (6th Edition) Blitzer

a. zeros: $x=-2$, odd multiplicity, $x=1$, odd multiplicity, $x=4$, odd multiplicity, b. $y=(x+2)(x-1)(x-4)$ c. $y=8$
Using the graph given in the exercise, we have: a. zeros: $x=-2$, odd multiplicity, $x=1$, odd multiplicity, $x=4$, odd multiplicity, b. We can write an equation as $y=(x+2)(x-1)(x-4)$ c. The y-intercept can be found as $y=8$ from the above equation by letting $x=0$ and by reading from the graph.