#### Answer

The required parabola is shown below:

#### Work Step by Step

Use the steps shown below to determine the graph of the quadratic equation.
Step 1:
The quadratic function can be written as $f\left( x \right)=a{{\left( x-h \right)}^{2}}+k$ corresponding to which the graph is a parabola whose vertex is at $\left( h,k \right)$. Therefore, the vertex of the parabola $y={{\left( x-3 \right)}^{2}}+1$ is $\left( h,k \right)=\left( 3,1 \right)$.
Step 2:
The parabola is also symmetric with respect to the line $x=h$. So, the provided parabola is symmetric to $x=3$.
Step 3:
If $a>0$ , the parabola opens upward and if $a<0$ then the parabola opens downward. Also, if $\left| a \right|$ is small, the parabola opens more flatly than if $\left| a \right|$ is large.
And, from the provided equation of the function, it is observed that the graph opens upwards as $a>0$.
Step 4:
So, we have the above steps lead to the parabola that opens upwards and has a vertex at $\left( 3,1 \right)$. Hence, the required parabola is shown above.