Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 2 - Section 2.2 - Quadratic Functions - Exercise Set - Page 330: 47

Answer

The Domain of the function is $\left( -\infty ,\infty \right)$ and its Range is $\left( -\infty ,-6 \right]$

Work Step by Step

We have to find the range of the function; we use the vertex of the parabola, which is $\left( 10,-6 \right)$. Since the parabola opens upwards, the maximum value of the function is given by the y-coordinate of the vertex. Thus, the maximum value is $-6$. The minimum value of the function would be $-\infty $. Thus, the range of the function is $\left( -\infty ,-6 \right]$. For the domain, see the values of the function at which the function is defined. The function is defined at all real values. Thus, the domain of the function is $\left( -\infty ,\infty \right)$. Thus, the range of the function is $\left( -\infty ,-6 \right]$ and its domain is $\left( -\infty ,\infty \right)$.
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