Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 2 - Review Exercises - Page 432: 84


$ P(x)=\dfrac{2x^2+2000}{x}$

Work Step by Step

Consider $ x $ and $ y $ to be the width and height. Thus, $ Area = width \times height=xy $ so, $ y= \dfrac{1000}{x}$ This implies that $ P(x)=2x+\dfrac{2000}{x}=\dfrac{2x^2+2000}{x}$ Therefore, $ P(x)=\dfrac{2x^2+2000}{x}$
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