## Precalculus (6th Edition) Blitzer

$\dfrac{6x+6}{x(x+3)}$
We are given the function $T(x)=\dfrac{4}{x+3}+\dfrac{2}{x}$ This implies that $T(x)=\dfrac{4}{x+3}+\dfrac{2}{x}=\dfrac{4x+2(x+3)}{x(x+3)}$ Therefore, $T(x)=\dfrac{4x+2x+6}{x(x+3)}=\dfrac{6x+6}{x(x+3)}$