Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 2 - Review Exercises - Page 430: 42


quotient $2x^2-4x+1$, remainder $-10$

Work Step by Step

Step 1. Using long division as shown in the figure, we have $\frac{10x^3-26x^2+17x-13}{5x-3}=2x^2-4x+1+\frac{-10}{5x-3}$ Step 2. We can identify the quotient as $2x^2-4x+1$ and the remainder as $-10$
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