#### Answer

$x=-5$ (multiplicity 1), crosses the x-axis.
$x=5$ (multiplicity 2), touches the x-axis and turns around.

#### Work Step by Step

Step 1. Factor the given function as
$f(x)=x^2(x-5)-25(x-5)=(x-5)^2(x+5)$
Step 2. We can identify its zeros as $x=-5$ (multiplicity 1) and $x=5$ (multiplicity 2).
Step 3. For $x=-5$, the graph crosses the x-axis.
Step 4. For $x=5$, the graph touches the x-axis and turns around.