## Precalculus (6th Edition) Blitzer

$x=-5$ (multiplicity 1), crosses the x-axis. $x=5$ (multiplicity 2), touches the x-axis and turns around.
Step 1. Factor the given function as $f(x)=x^2(x-5)-25(x-5)=(x-5)^2(x+5)$ Step 2. We can identify its zeros as $x=-5$ (multiplicity 1) and $x=5$ (multiplicity 2). Step 3. For $x=-5$, the graph crosses the x-axis. Step 4. For $x=5$, the graph touches the x-axis and turns around.