## Precalculus (6th Edition) Blitzer

The value of the function $f\left( x \right)=\frac{{{x}^{2}}-6x+8}{x-4}$ approaches to the integer 2 as x approaches to 4. When the value of x is 4, the denominator of the function becomes zero due to which the function becomes undefined.
The graph of the function $f\left( x \right)=\frac{{{x}^{2}}-6x+8}{x-4}$ is undefined at $x=4$. The value of the function $f\left( x \right)$ approaches to the integer $2$ as the value of $x$ approaches to $4$.