## Precalculus (6th Edition) Blitzer

We know that the situation involves making choices with eight questions. We use the fundamental counting principle to find the number of ways to answer the questions on the test. Multiply the number of choices for each of the eight questions. That is, \begin{align} & 3\times 3\times 3\times 3\times 3\times 3\times 3\times 3={{3}^{8}} \\ & =6561 \end{align} Hence, there are 6561 different ways to answer the questions.