## Precalculus (6th Edition) Blitzer

We know that the situation involves making choices with five questions. We use the fundamental counting principle to find the number of ways to answer the questions on the test. Multiply the number of choices for each of the five questions. That is, \begin{align} & 3\times 3\times 3\times 3\times 3={{3}^{5}} \\ & =243 \end{align} Hence, there are 243 different ways to answer the question.