Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 10 - Section 10.5 - The Binomial Theorum - Exercise Set - Page 1094: 88


See graph and explanations.

Work Step by Step

Step 1. Given $f(x)=-2(x-1)^2(x+3)$, we test for symmetry: $f(-x)=-2(-x-1)^2(-x+3)=2(x+1)^2(x-3)$; no symmetry. Step 2. End behavior: the leading term $-2x^3$, rises to the left and falls to the right. Step 3. The x-intercepts are: $x=-3, 1$. The graph crosses the x-axis at $x=-3$, and touches/returns at $x=1$. Step 4. The y-intercept: $f(0)=-2(1)(3)=-6$ Step 5. The maximum number of turns: $n-1=2$ Step 6. We use the test points as necessary to graph the function as shown in the figure.
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