Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 10 - Section 10.3 - Geoetric Sequences and Series - Concept and Vocabulary Check - Page 1073: 9

Answer

$1,-3,9,-27,81,...$ Geometric.

Work Step by Step

When we observe the sequence carefully, we see that the difference between two consecutive terms is not the same. Thus, the common ratio will be computed as $1,-3,9,-27,81,...$ Now, ${{a}_{1}}=1,{{a}_{2}}=-3,{{a}_{3}}=9,{{a}_{4}}=-27,{{a}_{5}}=81,...$ So, $\begin{align} & \frac{{{a}_{2}}}{{{a}_{1}}}=\frac{\left( -3 \right)}{1} \\ & =-3 \\ & \frac{{{a}_{3}}}{{{a}_{2}}}=\frac{9}{\left( -3 \right)} \\ & =-3 \end{align}$ $\begin{align} & \frac{{{a}_{4}}}{{{a}_{3}}}=\frac{\left( -27 \right)}{9} \\ & =-3 \\ & \frac{{{a}_{5}}}{{{a}_{4}}}=\frac{81}{\left( -27 \right)} \\ & =-3 \end{align}$ Therefore, the common ratio is -3. Hence, the sequence is Geometric.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.