Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 10 - Section 10.3 - Geoetric Sequences and Series - Concept and Vocabulary Check - Page 1073: 7

Answer

$4,8,12,16,20,...$ Arithmetic.

Work Step by Step

When we observe the sequence carefully, it is seen that the difference between two consecutive terms is the same in the series $4,8,12,16,20,...$ Now, $\begin{align} & {{a}_{1}}=4,{{a}_{2}}=8, \\ & {{a}_{3}}=12,{{a}_{4}}=16 \\ & {{a}_{5}}=20,... \\ \end{align}$ Then, $\begin{align} & {{a}_{2}}-{{a}_{1}}=8-4 \\ & =4 \\ & {{a}_{3}}-{{a}_{2}}=12-8 \\ & =4 \end{align}$ $\begin{align} & {{a}_{4}}-{{a}_{3}}=16-12 \\ & =4 \\ & {{a}_{5}}-{{a}_{4}}=20-16 \\ & =4 \end{align}$ Therefore, the common difference is 4. Hence, the sequence is Arithmetic.
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