Answer
$a_n=3n-2$
Work Step by Step
We know that $a_n=a_1+(n-1) d$
Here, we have $a_{2}=a_1+d=4; a_{6}=a_1+5d=16$
Thus,we have
$a_1+5d-a_1-d=16-12$
or, $4d=12 \implies d=3$
and $a_1=4-d=4-3=1$
Now, $a_n=1+(n-1) (3)=3n-2$
Precalculus (6th Edition) Blitzer
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13446-914-3
ISBN 13:
978-0-13446-914-0
Chapter 10 - Section 10.2 - Arithmetic Sequences - Exercise Set - Page 1060: 59
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