Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 10 - Section 10.2 - Arithmetic Sequences - Exercise Set - Page 1060: 54

Answer

19 terms

Work Step by Step

We know that $a_n=a_1+(n-1) d$ Here, we have $a_{1}=3; a_n=93; d=5$ Thus, we have $93=3+(n-1)(5)$ or, $5n-2=93 \implies n=19$ Hence, there are $19$ terms
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