## Precalculus (6th Edition) Blitzer

${{a}_{2}}=2{{a}_{1}}-4=\underline{2}$.
The second term of the sequence can be obtained by putting $n=2$. Then, for the third term, simply put $n=3$, and so on for other terms. We are given that ${{a}_{n}}=2{{a}_{n-1}}-4$ and ${{a}_{1}}=3$. Now, to find the second term, put $n=2$; \begin{align} & {{a}_{2}}=2{{a}_{2-1}}-4 \\ & =2{{a}_{1}}-4 \\ & =2\left( 3 \right)-4 \\ & =2 \end{align}