## Precalculus (6th Edition) Blitzer

The current when the resistance is $10$ ohms is $11$ Amperes.
We have to write the relation between $I$ and $R$ as, \begin{align} & I\propto \frac{1}{R} \\ & I=\frac{k}{R} \end{align} Where $k$ is the constant of proportionality. Put the value of $R=22$ and $I=5$ in the equation to get the value of $k$ as: \begin{align} & 5=\frac{k}{22} \\ & k=5\cdot 22 \\ & k=110 \end{align} So, the equation becomes $I=\frac{110}{R}$. Then, one has to find the value of $I$ when $R$ is $10$ as: \begin{align} & I=\frac{110}{10} \\ & =11 \end{align} Thus, the current when resistance is $10$ ohms is $11$ Amperes.