Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 10 - Cumulative Review Exercises - Page 1127: 5


The required solution for $ x=-1$ and $ x=-3$ is $ f\left( x \right)=1$.

Work Step by Step

From the graph one can see that when $ f\left( x \right)=1$ (that is, the y-coordinate is 1), the x values are $-1$ and $-3$. Thus, the value of x for which $ f\left( x \right)=1$ is $ x=-1$ and $ x=-3$.
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