## Precalculus (6th Edition) Blitzer

We know that an even function equates $f\left( -x \right)=f\left( x \right)$, while an odd function satisfies $f\left( -x \right)=-f\left( x \right)$; that is, it is the same in the 1st and the 3rd quadrant. One can observe that the graph has no symmetry about the y-axis nor symmetry about the origin. Thus, the provided graph is neither even nor odd.