Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 1 - Section 1.5 - More on Slope - Exercise Set - Page 227: 46

Answer

The solution set is $\left\{ 45 \right\}$.

Work Step by Step

Consider the equation $24+3\left( x+2 \right)=5\left( x-12 \right)$. Apply the distributive property $\begin{align} & 24+3\left( x+2 \right)=5\left( x-12 \right) \\ & 24+3\left( x \right)+3\left( 2 \right)=5\left( x \right)+5\left( -12 \right) \\ & 24+3x+6=5x-60 \end{align}$ Collect all variables on one side. $\begin{align} & 24+3x+6=5x-60 \\ & 30+60=5x-3x \\ & 90=2x \end{align}$ Divide both sides of the equation by $2$. $\begin{align} & \frac{90}{2}=\frac{2x}{2} \\ & 45=x \end{align}$ The solution of the equation $24+3\left( x+2 \right)=5\left( x-12 \right)$ is $45$. Check the obtained solution by substituting $x=45$ in the equation $24+3\left( x+2 \right)=5\left( x-12 \right)$ $\begin{align} & \text{ }24+3\left( x+2 \right)=5\left( x-12 \right) \\ & 24+3\left( 45+2 \right)\overset{?}{\mathop{=}}\,5\left( 45-12 \right) \\ & \text{ }24+141\overset{?}{\mathop{=}}\,165 \\ & \text{ }165\overset{?}{\mathop{=}}\,165 \\ \end{align}$ This is true. Hence, the value satisfies the above equation.
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