Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 1 - Section 1.5 - More on Slope - Exercise Set - Page 227: 40

Answer

No, the provided statement does not make any sense; the lines are not perpendicular.

Work Step by Step

Consider that the slope of one line is $-\frac{3}{5}$ and the slope of the second line is $-\frac{5}{3}$. If the product of their slope is $-1$, then the given two lines will be perpendicular. That is, ${{m}_{1}}\cdot {{m}_{2}}=-1$. So, the product of their slopes is, $\begin{align} & \left( -\frac{3}{5} \right)\times \left( -\frac{5}{3} \right)\overset{?}{\mathop{=}}\,-1. \\ & 1\ne -1 \end{align}$ Hence, the given lines are not perpendicular. So, the statement does make any sense.
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