## Precalculus (6th Edition) Blitzer

The equation of the line is $y=4x-17$.
The general slope–intercept form of the line is given by: $y-{{y}_{0}}=m\left( x-{{x}_{0}} \right)$ The line is passing through the point $\left( 3,-5 \right)$ and the slope is the negative reciprocal of $-\frac{1}{4}$. So the slope of the line is 4. Now, substitute $\left( {{x}_{0}},{{y}_{0}} \right)=\left( 3,-5 \right)$ and $m=4$ in equation as shown below: \begin{align} & y+5=4\left( x-3 \right) \\ & y+5=4x-12 \\ & y=4x-12-5 \\ & y=4x-17 \end{align} Hence, the slope–intercept form of the line is given by $y=4x-17$.