Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 1 - Section 1.4 - Linear Functions and Slope - Exercise Set - Page 216: 120


$(-7,1)$; see graph.

Work Step by Step

Step 1. From $3|2x+6|-9\lt 15$, we have $|2x+6|\lt 8$, which can be written as $-8\lt 2x+6 \lt 8$ Step 2. Solving the above inequality, we have $-14\lt 2x \lt 2$ and $-7\lt x \lt 1$, or in interval notation $(-7,1)$. Step 3. We can graph the above solution on a number line as shown.
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