## Precalculus (6th Edition) Blitzer

Consider the given equation $x=2$ Calculate three points of the function in order to plot the graph of $x=2$. Substitute $y=1$ , $x=2$ So, the one point that satisfies the equation $x=2$ is $\left( 2,1 \right)$. Substitute $y=0$ , $x=2$ So, the second point that satisfies the equation $x=2$ is $\left( 2,0 \right)$. Substitute $y=2$ , $x=2$ So, the third point that satisfies the equation $x=2$ is $\left( 2,2 \right)$. All the points that are solutions of $x=2$ will have their ordinate as 2. That is, they will be of the form $\left( 2,a \right)$. Locate all three points $\left( 2,1 \right)$, $\left( 2,0 \right)$, and $\left( 2,2 \right)$, and connect them by a straight line. The graph of the given equation $x=2$ will be a vertical line as shown below.