## Precalculus (6th Edition) Blitzer

The two points which are selected for the calculation of the slope are $\left( {{x}_{1}},{{y}_{1}} \right)=\left( 1.06,2.81 \right)$and$\left( {{x}_{2}},{{y}_{2}} \right)=\left( 1.7,0.89 \right)$. Now, the slope of a line using the two points is calculated as follows: \begin{align} & m=\frac{{{y}_{1}}-{{y}_{2}}}{{{x}_{1}}-{{x}_{2}}} \\ & =\frac{2.81-0.89}{1.06-1.7} \\ & =\frac{1.92}{-0.64} \\ & =-3 \end{align} The equation of the line is given in the slope-intercept form. From that equation, the slope of the line is -3. Also, the slope of the line calculated using the two points in the line is -3.