Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 1 - Section 1.4 - Linear Functions and Slope - Exercise Set - Page 215: 101

Answer

The graph obtained is as shown below:
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Work Step by Step

The two points which are selected for the calculation of the slope are \[\left( {{x}_{1}},{{y}_{1}} \right)=\left( 1.06,2.81 \right)\]and\[\left( {{x}_{2}},{{y}_{2}} \right)=\left( 1.7,0.89 \right)\]. Now, the slope of a line using the two points is calculated as follows: \[\begin{align} & m=\frac{{{y}_{1}}-{{y}_{2}}}{{{x}_{1}}-{{x}_{2}}} \\ & =\frac{2.81-0.89}{1.06-1.7} \\ & =\frac{1.92}{-0.64} \\ & =-3 \end{align}\] The equation of the line is given in the slope-intercept form. From that equation, the slope of the line is -3. Also, the slope of the line calculated using the two points in the line is -3.
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