Answer
The graph of the equation $x={{y}^{2}}+6$ is symmetric to the x-axis only.
Work Step by Step
Consider the equation, $x={{y}^{2}}+6$
Check symmetry about the y-axis:
An equation is symmetric about the y-axis if $-x$ is substituted in the function and the result is an equivalent equation.
Substitute $x=-x$ in the equation,
$\begin{align}
& -x={{y}^{2}}+6 \\
& -x={{y}^{2}}+6
\end{align}$
Therefore, the equation is not symmetric about the y-axis.
Now, check symmetry about the x-axis:
An equation is symmetric about the x-axis, if $-y$ is substituted in the function and it leads to an equivalent equation.
Substitute $y=-y$ ,
$\begin{align}
& x={{\left( -y \right)}^{2}}+6 \\
& ={{y}^{2}}+6
\end{align}$
Therefore, the equation is symmetric about the x-axis.
Now, check symmetry about the origin:
An equation is symmetric about the origin if $x=-x,y=-y$ and it leads to an equivalent equation.
Substitute $x=-x,y=-y$
$\begin{align}
& -x={{\left( -y \right)}^{2}}+6 \\
& -x={{y}^{2}}+6 \\
\end{align}$
Therefore, the equation is not symmetric about the origin.
Hence, the equation is only symmetric about the x-axis.
