Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 1 - Section 1.3 - More on Functions and Their Graphs - Exercise Set - Page 196: 34


The function is an odd function.

Work Step by Step

It can be seen that the points of the graph are images of each other about the origin. In the given graph it can observed that the function is symmetrical with respect to the origin. So, the graph of the function belongs to the graph of an odd function. Thus, by the symmetry of the graph, f is an odd function.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.