Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 1 - Section 1.2 - Basics of Functions and Their Graphs - Exercise Set - Page 176: 23


$y$ is a function of $x$

Work Step by Step

Solve for $y$. Factor out $y$ on the left side of the equation to obtain: $y(x+2)=1$ Divide $x+2$ on both sides to obtain: $\dfrac{y(x+2)}{x+2} = \dfrac{1}{x+2} \\y = \dfrac{1}{x+2}$ Note that when you assign any real number value (except -2) to $x$, the equation will give only one value of $y$. Thus, the given equation represents $y$ as a function of $x$.
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