## Precalculus (6th Edition) Blitzer

Published by Pearson

# Chapter 1 - Section 1.2 - Basics of Functions and Their Graphs - Exercise Set - Page 176: 13

#### Answer

$y$ is a function of $x$.

#### Work Step by Step

Solve for $y$ by adding $-x^2$ on both sides of the equation to obtain $y=-x^2+16$. Note that when you assign any real number value to $x$, the equation will give only one value of $y$. Thus, the given equation represents $y$ as a function of $x$.

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