Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 1 - Section 1.10 - Modeling with Functions - Exercise Set - Page 293: 29

Answer

The expression of cost for the contractor to build the walls of a warehouse which have a floor area of $4000\text{ square feet}$ is $C\left( x \right)=475x+\frac{1400000}{x}$.

Work Step by Step

The expression of cost for the contractor to build the walls of a warehouse which have a floor area of $4000\text{ square feet}$ is $C\left( x \right)=475x+\frac{1400000}{x}$.a Let the length of the warehouse be x and breadth of the warehouse be $y$. Write the expression for the floor area of the warehouse. $xy=4000$ Calculate y in terms of x. $y=\frac{4000}{x}$ Write the expression for the cost of walls considering the cost to construct the outer wall is $\$175$ and for the inner wall is $\$125$. $C=175\left( 2x+2y \right)+125x$ Substitute $\frac{4000}{x}$ for $y$. $C=175\left[ 2x+2\left( \frac{4000}{x} \right) \right]+125x$ The cost is a function of x, so it can be expressed as, $\begin{align} & C\left( x \right)=175\left[ 2x+2\left( \frac{4000}{x} \right) \right]+125x \\ & C\left( x \right)=350x+\frac{1400000}{x}+125x \\ & =475x+\frac{1400000}{x} \end{align}$ Hence, the expression of cost for the contractor to build the walls of a warehouse which have a floor area of $4000\text{ square feet}$ is $C\left( x \right)=475x+\frac{1400000}{x}$.
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