Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 1 - Section 1.10 - Modeling with Functions - Exercise Set - Page 293: 22

Answer

The expression for the area of the rectangular field in terms of one of the dimensions of the field x is $A\left( x \right)=-{{x}^{2}}+300x$.

Work Step by Step

Let the length of the field be $x$ and breadth of the field be $y$. Consider the perimeter of the rectangular field which will equal to the fencing required to enclose the field. $2x+2y=600$ Calculate $y$ in terms of x. $\begin{align} & 2y=600-2x \\ & y=\frac{600-2x}{2} \\ & y=300-x \end{align}$ Consider the area of the rectangular field. $A=xy$ Substitute $300-x$ for y. $A=x\left( 300-x \right)$ Because A is a function of x, it can be written as, $\begin{align} & A\left( x \right)=x\left( 300-x \right) \\ & =300x-{{x}^{2}} \\ & =-{{x}^{2}}+300x \end{align}$ Hence, the expression for the area of the rectangular field in terms of one of the dimensions of the field x is $A\left( x \right)=-{{x}^{2}}+300x$.
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