Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 1 - Review Exercises - Page 301: 47

Answer

The difference quotient of the given function is equal to 8.

Work Step by Step

To get the value of $f\left( x+h \right)$, put $x+h$ in place of x, and then substitute in the given expression: So, $\begin{align} & f\left( x+h \right)=8\left( x+h \right)-11 \\ & =8x+8h-11. \end{align}$ Now, $\begin{align} & \frac{f\left( x+h \right)-f\left( x \right)}{h}=\frac{8x+8h-11-8x+11}{h} \\ & =\frac{8h}{h} \\ & =8. \end{align}$ Therefore, the difference quotient of the given function is equal to 8.
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