Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 9 - Polar Coordinates; Vectors - 9.6 Vectors in Space - 9.6 Assess Your Understanding - Page 625: 37

Answer

$\sqrt{22}.$

Work Step by Step

The magnitude $||v||$ of a vector $v=ai+bj+ck$, can be computed using the formula $||v||=\sqrt{a^2+b^2+c^2}$. Hence, using the formula above gives $||v||=\sqrt{(-2)^2+3^2+(-3)^2}\\||v||=\sqrt{4+9+9}\\||v||=\sqrt{22}.$
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