Precalculus (10th Edition)

$(-2,-3,1),(-2,7,0),(-6,-3,0),(-2,7,1),(-6,-3,1),(-6,7,0).$
If the opposite vertices of a rectangular box are: $(a,b,c)$ and $(x,y,z)$ then the other six vertices will have coordinates(because the other $6$ vertices must "inherit" each coordinate from either of the opposite vertices): $(a,b,z),(a,y,c),(x,b,c),(x,y,c),(x,b,z),(a,y,z).$ Hence here the other vertices are: $(-2,-3,1),(-2,7,0),(-6,-3,0),(-2,7,1),(-6,-3,1),(-6,7,0).$